The equivalent weight of $Zn(OH)_2$ in the following reaction is equal to its: $Zn(OH)_2 + HNO_3 \to Zn(OH)(NO_3) + H_2O$
- A$\frac{\text{Formula weight}}{2}$
- B$\frac{\text{Formula weight}}{1}$
- C$3 \times \text{Formula weight}$
- D$2 \times \text{Formula weight}$
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